What are the solutions to the equation (x+8)^2=-x-2 ?

The solutions to the equation (x+8)^2=-x-2 are x=-6,x=-11

Find the zeros of (x+8)^2=-x-2

The zeros of (x+8)^2=-x-2 are x=-6,x=-11

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(x + 8)^{2} = - x - 2

x = - 6, x = - 11

Solution steps

(x + 8)^{2} = - x - 2

Expand

(x + 8)^{2} : x^{2} + 16 x + 64

x^{2} + 16 x + 64 = - x - 2

Move

2

to the left side

x^{2} + 16 x + 66 = - x

Move

x

to the left side

x^{2} + 17 x + 66 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot 66}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot 66 = 5

x_{1, 2} = \frac{- 17 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 17 + 5}{2 \cdot 1}, x_{2} = \frac{- 17 - 5}{2 \cdot 1}

x = \frac{- 17 + 5}{2 \cdot 1} : - 6

x = \frac{- 17 - 5}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = - 6, x = - 11

3 x^{2} + 7 x - 6 = 0

(3 x + 2) (2 x - 5) = (4 x - 1) (5 x + 6)

x^{2} = - 31

0 = - 4.8992 x^{2} + 2.624 x + 0.00003

2 x^{2} - 3 = 3 x^{2} + 1

What are the solutions to the equation (x+8)^2=-x-2 ?
The solutions to the equation (x+8)^2=-x-2 are x=-6,x=-11
Find the zeros of (x+8)^2=-x-2
The zeros of (x+8)^2=-x-2 are x=-6,x=-11