What are the solutions to the equation 2x^2-3x=10 ?

The solutions to the equation 2x^2-3x=10 are x=(3+sqrt(89))/4 ,x=(3-sqrt(89))/4

Find the zeros of 2x^2-3x=10

The zeros of 2x^2-3x=10 are x=(3+sqrt(89))/4 ,x=(3-sqrt(89))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 3 x = 10

x = \frac{3 + 89}{4}, x = \frac{3 - 89}{4}

Decimal Notation

x = 3.10849 \dots, x = - 1.60849 \dots

Solution steps

2 x^{2} - 3 x = 10

Move

10

to the left side

2 x^{2} - 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 10) = 89

x_{1, 2} = \frac{- ( - 3 ) \pm 89}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 89}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 89}{2 \cdot 2}

x = \frac{- ( - 3 ) + 89}{2 \cdot 2} : \frac{3 + 89}{4}

x = \frac{- ( - 3 ) - 89}{2 \cdot 2} : \frac{3 - 89}{4}

The solutions to the quadratic equation are:

x = \frac{3 + 89}{4}, x = \frac{3 - 89}{4}

x (2 x + 5) = 4 (x + 7)

10 x^{2} + 10 x^{2} + 1 = 0

7 n^{2} - 7 = 105

2 x^{2} - 4 x + 13

(3 x - 1)^{2} + x (x - 3) = - 1

What are the solutions to the equation 2x^2-3x=10 ?
The solutions to the equation 2x^2-3x=10 are x=(3+sqrt(89))/4 ,x=(3-sqrt(89))/4
Find the zeros of 2x^2-3x=10
The zeros of 2x^2-3x=10 are x=(3+sqrt(89))/4 ,x=(3-sqrt(89))/4