What are the solutions to the equation x^2-(k+2)x+k+1=0 ?

The solutions to the equation x^2-(k+2)x+k+1=0 are x=k+1,x=1

Find the zeros of x^2-(k+2)x+k+1=0

The zeros of x^2-(k+2)x+k+1=0 are x=k+1,x=1

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x^{2} - (k + 2) x + k + 1 = 0

x = k + 1, x = 1

Solution steps

x^{2} - (k + 2) x + k + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - k - 2 ) \pm ( - k - 2 ) ^{2} - 4 \cdot 1 \cdot ( k + 1 )}{2 \cdot 1}

Simplify

(- k - 2)^{2} - 4 \cdot 1 \cdot (k + 1) : k

x_{1, 2} = \frac{- ( - k - 2 ) \pm k}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - k - 2 ) + k}{2 \cdot 1}, x_{2} = \frac{- ( - k - 2 ) - k}{2 \cdot 1}

x = \frac{- ( - k - 2 ) + k}{2 \cdot 1} : k + 1

x = \frac{- ( - k - 2 ) - k}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = k + 1, x = 1

x^{2} - 5 = 3 x

(x - 13)^{2} = 400

x^{2} - 3 x - 0.9 = 0

4 + 7 x - x^{2} = - \frac{x}{2}

- 6.4 X^{2} + 128 X - 546.67 = 0

What are the solutions to the equation x^2-(k+2)x+k+1=0 ?
The solutions to the equation x^2-(k+2)x+k+1=0 are x=k+1,x=1
Find the zeros of x^2-(k+2)x+k+1=0
The zeros of x^2-(k+2)x+k+1=0 are x=k+1,x=1