What is ((a^{2/3}b^{-2})^3)^{-1} ?

The solution to ((a^{2/3}b^{-2})^3)^{-1} is (b^6)/(a^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((a^{2/3}b^{-2})^3)^{-1}

simplify

((a^{\frac{2}{3}} b^{- 2})^{3})^{- 1}

\frac{b ^{6}}{a ^{2}}

Solution steps

((a^{\frac{2}{3}} b^{- 2})^{3})^{- 1}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (a^{\frac{2}{3}} b^{- 2})^{3 (- 1)}

3 (- 1) = - 3

= (a^{\frac{2}{3}} b^{- 2})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(a^{\frac{2}{3}} b^{- 2})^{- 3} = \frac{1}{( a ^{\frac{2}{3}} b ^{- 2} ) ^{3}}

= \frac{1}{( a ^{\frac{2}{3}} b ^{- 2} ) ^{3}}

Simplify

(a^{\frac{2}{3}} b^{- 2})^{3} : \frac{a ^{2}}{b ^{6}}

= \frac{1}{\frac{a ^{2}}{b ^{6}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{b ^{6}}{a ^{2}}

∣ 6 y - 3 ∣ + 8 = 35

∣ x - 3 ∣ > 3

\frac{( - 18 a b ^{3} )}{( - 2 ab )}

9 x - 6 = 4 x + 19

\frac{n}{n + 1} + \frac{1}{( n + 1 ) ( n + 2 )}

What is ((a^{2/3}b^{-2})^3)^{-1} ?
The solution to ((a^{2/3}b^{-2})^3)^{-1} is (b^6)/(a^2)