What are the solutions to the equation 2t^2-7t=12 ?

The solutions to the equation 2t^2-7t=12 are t=(7+sqrt(145))/4 ,t=(7-sqrt(145))/4

Find the zeros of 2t^2-7t=12

The zeros of 2t^2-7t=12 are t=(7+sqrt(145))/4 ,t=(7-sqrt(145))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 t^{2} - 7 t = 12

t = \frac{7 + 145}{4}, t = \frac{7 - 145}{4}

Solution steps

2 t^{2} - 7 t = 12

Move

12

to the left side

2 t^{2} - 7 t - 12 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 12) = 145

t_{1, 2} = \frac{- ( - 7 ) \pm 145}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- ( - 7 ) + 145}{2 \cdot 2}, t_{2} = \frac{- ( - 7 ) - 145}{2 \cdot 2}

t = \frac{- ( - 7 ) + 145}{2 \cdot 2} : \frac{7 + 145}{4}

t = \frac{- ( - 7 ) - 145}{2 \cdot 2} : \frac{7 - 145}{4}

The solutions to the quadratic equation are:

t = \frac{7 + 145}{4}, t = \frac{7 - 145}{4}

z^{2} - 2 z = 3

3 x^{2} - 6 x - 7 = x^{2} + 3 x - x (x + 1) + 3

x, 3 x^{2} - 3 y^{2} = 0

2 x^{2} - 2 x = x^{2} + 2 x + 1

3 (x + 2)^{2} + 4 = 40

What are the solutions to the equation 2t^2-7t=12 ?
The solutions to the equation 2t^2-7t=12 are t=(7+sqrt(145))/4 ,t=(7-sqrt(145))/4
Find the zeros of 2t^2-7t=12
The zeros of 2t^2-7t=12 are t=(7+sqrt(145))/4 ,t=(7-sqrt(145))/4