What are the solutions to the equation 7c^2=c+6 ?

The solutions to the equation 7c^2=c+6 are c=1,c=-6/7

Find the zeros of 7c^2=c+6

The zeros of 7c^2=c+6 are c=1,c=-6/7

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7 c^{2} = c + 6

c = 1, c = - \frac{6}{7}

Solution steps

7 c^{2} = c + 6

Move

6

to the left side

7 c^{2} - 6 = c

Move

c

to the left side

7 c^{2} - 6 - c = 0

Write in the standard form

a x^{2} + b x + c = 0

7 c^{2} - c - 6 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 7 ( - 6 )}{2 \cdot 7}

(- 1)^{2} - 4 \cdot 7 (- 6) = 13

c_{1, 2} = \frac{- ( - 1 ) \pm 13}{2 \cdot 7}

Separate the solutions

c_{1} = \frac{- ( - 1 ) + 13}{2 \cdot 7}, c_{2} = \frac{- ( - 1 ) - 13}{2 \cdot 7}

c = \frac{- ( - 1 ) + 13}{2 \cdot 7} : 1

c = \frac{- ( - 1 ) - 13}{2 \cdot 7} : - \frac{6}{7}

The solutions to the quadratic equation are:

c = 1, c = - \frac{6}{7}

4 c^{2} + c - 6 = 0

9 x + 28 = 9 x^{2}

11 x = 3 x^{2} - 9

x, x^{2} - 4 x + 2^{t} = 0

x, x^{2} + y^{2} + 2 x = - 1

What are the solutions to the equation 7c^2=c+6 ?
The solutions to the equation 7c^2=c+6 are c=1,c=-6/7
Find the zeros of 7c^2=c+6
The zeros of 7c^2=c+6 are c=1,c=-6/7