What are the solutions to the equation 24x^2-2x+10=0 ?

The solutions to the equation 24x^2-2x+10=0 are x= 1/24+i(sqrt(239))/(24),x= 1/24-i(sqrt(239))/(24)

Find the zeros of 24x^2-2x+10=0

The zeros of 24x^2-2x+10=0 are x= 1/24+i(sqrt(239))/(24),x= 1/24-i(sqrt(239))/(24)

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24 x^{2} - 2 x + 10 = 0

x = \frac{1}{24} + i \frac{239}{24}, x = \frac{1}{24} - i \frac{239}{24}

Solution steps

24 x^{2} - 2 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 24 \cdot 10}{2 \cdot 24}

Simplify

(- 2)^{2} - 4 \cdot 24 \cdot 10 : 2239 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 239 i}{2 \cdot 24}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 239 i}{2 \cdot 24}, x_{2} = \frac{- ( - 2 ) - 2 239 i}{2 \cdot 24}

x = \frac{- ( - 2 ) + 2 239 i}{2 \cdot 24} : \frac{1}{24} + i \frac{239}{24}

x = \frac{- ( - 2 ) - 2 239 i}{2 \cdot 24} : \frac{1}{24} - i \frac{239}{24}

The solutions to the quadratic equation are:

x = \frac{1}{24} + i \frac{239}{24}, x = \frac{1}{24} - i \frac{239}{24}

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What are the solutions to the equation 24x^2-2x+10=0 ?
The solutions to the equation 24x^2-2x+10=0 are x= 1/24+i(sqrt(239))/(24),x= 1/24-i(sqrt(239))/(24)
Find the zeros of 24x^2-2x+10=0
The zeros of 24x^2-2x+10=0 are x= 1/24+i(sqrt(239))/(24),x= 1/24-i(sqrt(239))/(24)