What are the solutions to the equation x^2-2(x-6)=4x+4 ?

The solutions to the equation x^2-2(x-6)=4x+4 are x=4,x=2

Find the zeros of x^2-2(x-6)=4x+4

The zeros of x^2-2(x-6)=4x+4 are x=4,x=2

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x^{2} - 2 (x - 6) = 4 x + 4

x = 4, x = 2

Solution steps

x^{2} - 2 (x - 6) = 4 x + 4

Expand

x^{2} - 2 (x - 6) : x^{2} - 2 x + 12

x^{2} - 2 x + 12 = 4 x + 4

Move

4

to the left side

x^{2} - 2 x + 8 = 4 x

Move

4 x

to the left side

x^{2} - 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 8 = 2

x_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2}{2 \cdot 1} : 4

x = \frac{- ( - 6 ) - 2}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 4, x = 2

6 (5 x + x)^{2} - 42 = 0

7 x = 3 x^{2}

a^{2} = 225

2 x^{2} + 6 x - 8

x, 10 x^{2} + 10 y^{2} = 0

What are the solutions to the equation x^2-2(x-6)=4x+4 ?
The solutions to the equation x^2-2(x-6)=4x+4 are x=4,x=2
Find the zeros of x^2-2(x-6)=4x+4
The zeros of x^2-2(x-6)=4x+4 are x=4,x=2