What are the solutions to the equation (x+3)^2=9x^2 ?

The solutions to the equation (x+3)^2=9x^2 are x=-3/4 ,x= 3/2

Find the zeros of (x+3)^2=9x^2

The zeros of (x+3)^2=9x^2 are x=-3/4 ,x= 3/2

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(x + 3)^{2} = 9 x^{2}

x = - \frac{3}{4}, x = \frac{3}{2}

Solution steps

(x + 3)^{2} = 9 x^{2}

Expand

(x + 3)^{2} : x^{2} + 6 x + 9

x^{2} + 6 x + 9 = 9 x^{2}

Move

9 x^{2}

to the left side

- 8 x^{2} + 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 8 ) \cdot 9}{2 ( - 8 )}

6^{2} - 4 (- 8) \cdot 9 = 18

x_{1, 2} = \frac{- 6 \pm 18}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 6 + 18}{2 ( - 8 )}, x_{2} = \frac{- 6 - 18}{2 ( - 8 )}

x = \frac{- 6 + 18}{2 ( - 8 )} : - \frac{3}{4}

x = \frac{- 6 - 18}{2 ( - 8 )} : \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{4}, x = \frac{3}{2}

2 q^{2} + 11 q + 13 = 0

3 (x + 1)^{2} - 1 = 11

y, x = (y - 5)^{2}

- 2 (6 x^{2} + 24) = 24

6 - 2 x + 3 x^{2} = 0

What are the solutions to the equation (x+3)^2=9x^2 ?
The solutions to the equation (x+3)^2=9x^2 are x=-3/4 ,x= 3/2
Find the zeros of (x+3)^2=9x^2
The zeros of (x+3)^2=9x^2 are x=-3/4 ,x= 3/2