What are the solutions to the equation x(3x-7)=6 ?

The solutions to the equation x(3x-7)=6 are x=3,x=-2/3

Find the zeros of x(3x-7)=6

The zeros of x(3x-7)=6 are x=3,x=-2/3

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x (3 x - 7) = 6

x = 3, x = - \frac{2}{3}

Solution steps

x (3 x - 7) = 6

Expand

x (3 x - 7) : 3 x^{2} - 7 x

3 x^{2} - 7 x = 6

Move

6

to the left side

3 x^{2} - 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 (- 6) = 11

x_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 3}

x = \frac{- ( - 7 ) + 11}{2 \cdot 3} : 3

x = \frac{- ( - 7 ) - 11}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = 3, x = - \frac{2}{3}

(2 x + 1)^{2} - x^{2} + 5 x - 10 = 0

64 a z^{2} - 81 a^{3} = 0

- 0.005 x^{2} + 0.101 x - 0.193 = 0

x^{2} - 6 x + 5 = - x^{2} + 4 x

x, z = - x^{2} - 2 y

What are the solutions to the equation x(3x-7)=6 ?
The solutions to the equation x(3x-7)=6 are x=3,x=-2/3
Find the zeros of x(3x-7)=6
The zeros of x(3x-7)=6 are x=3,x=-2/3