What are the solutions to the equation 2(2x-5)=-4x(x-1) ?

The solutions to the equation 2(2x-5)=-4x(x-1) are x=sqrt(5/2),x=-sqrt(5/2)

Find the zeros of 2(2x-5)=-4x(x-1)

The zeros of 2(2x-5)=-4x(x-1) are x=sqrt(5/2),x=-sqrt(5/2)

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2 (2 x - 5) = - 4 x (x - 1)

x = \frac{5}{2}, x = - \frac{5}{2}

Solution steps

2 (2 x - 5) = - 4 x (x - 1)

Expand

2 (2 x - 5) : 4 x - 10

Expand

- 4 x (x - 1) : - 4 x^{2} + 4 x

4 x - 10 = - 4 x^{2} + 4 x

Switch sides

- 4 x^{2} + 4 x = 4 x - 10

Move

4 x

to the left side

- 4 x^{2} = - 10

Divide both sides by

- 4

x^{2} = \frac{5}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{2}, x = - \frac{5}{2}

3 x^{2} + 5 x + 3

3 x - 6 = - x^{2}

0.1 n^{2} + 100 n + 8 = 60000

x, x^{2} y^{3} = 6^{12}

4.68 x^{2} - 15.5 x + 12.43 = 0

What are the solutions to the equation 2(2x-5)=-4x(x-1) ?
The solutions to the equation 2(2x-5)=-4x(x-1) are x=sqrt(5/2),x=-sqrt(5/2)
Find the zeros of 2(2x-5)=-4x(x-1)
The zeros of 2(2x-5)=-4x(x-1) are x=sqrt(5/2),x=-sqrt(5/2)