What are the solutions to the equation 3x+18=x^2 ?

The solutions to the equation 3x+18=x^2 are x=6,x=-3

Find the zeros of 3x+18=x^2

The zeros of 3x+18=x^2 are x=6,x=-3

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3 x + 18 = x^{2}

x = 6, x = - 3

Solution steps

3 x + 18 = x^{2}

Switch sides

x^{2} = 3 x + 18

Move

18

to the left side

x^{2} - 18 = 3 x

Move

3 x

to the left side

x^{2} - 18 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 18) = 9

x_{1, 2} = \frac{- ( - 3 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 9}{2 \cdot 1}

x = \frac{- ( - 3 ) + 9}{2 \cdot 1} : 6

x = \frac{- ( - 3 ) - 9}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 6, x = - 3

y, y^{2} + 6 y + 9 = x + 8

3 x^{2} - 5 (2 x + 7) = 0

3 b^{2} - b + 5 = 6

x, (2 x - 9 y)^{2} + 7 y = 27 x

3 y^{2} + 2 = 5 y

What are the solutions to the equation 3x+18=x^2 ?
The solutions to the equation 3x+18=x^2 are x=6,x=-3
Find the zeros of 3x+18=x^2
The zeros of 3x+18=x^2 are x=6,x=-3