What are the solutions to the equation 4x^2+72x+324=5x^2+48x+144 ?

The solutions to the equation 4x^2+72x+324=5x^2+48x+144 are x=-6,x=30

Find the zeros of 4x^2+72x+324=5x^2+48x+144

The zeros of 4x^2+72x+324=5x^2+48x+144 are x=-6,x=30

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4 x^{2} + 72 x + 324 = 5 x^{2} + 48 x + 144

x = - 6, x = 30

Solution steps

4 x^{2} + 72 x + 324 = 5 x^{2} + 48 x + 144

Move

144

to the left side

4 x^{2} + 72 x + 180 = 5 x^{2} + 48 x

Move

48 x

to the left side

4 x^{2} + 24 x + 180 = 5 x^{2}

Move

5 x^{2}

to the left side

- x^{2} + 24 x + 180 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 1 ) \cdot 180}{2 ( - 1 )}

2 4^{2} - 4 (- 1) \cdot 180 = 36

x_{1, 2} = \frac{- 24 \pm 36}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 24 + 36}{2 ( - 1 )}, x_{2} = \frac{- 24 - 36}{2 ( - 1 )}

x = \frac{- 24 + 36}{2 ( - 1 )} : - 6

x = \frac{- 24 - 36}{2 ( - 1 )} : 30

The solutions to the quadratic equation are:

x = - 6, x = 30

x, x^{2} = 3 x y - 6

9 x = 3 x^{2}

- 18 - 3 x + 6 x^{2} = 0

3 (x - 2)^{2} = 6

x (2 x - 1) = 10

What are the solutions to the equation 4x^2+72x+324=5x^2+48x+144 ?
The solutions to the equation 4x^2+72x+324=5x^2+48x+144 are x=-6,x=30
Find the zeros of 4x^2+72x+324=5x^2+48x+144
The zeros of 4x^2+72x+324=5x^2+48x+144 are x=-6,x=30