What are the solutions to the equation 4(x+3)^2+2=-6 ?

The solutions to the equation 4(x+3)^2+2=-6 are x=sqrt(2)i-3,x=-sqrt(2)i-3

Find the zeros of 4(x+3)^2+2=-6

The zeros of 4(x+3)^2+2=-6 are x=sqrt(2)i-3,x=-sqrt(2)i-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 (x + 3)^{2} + 2 = - 6

x = 2 i - 3, x = - 2 i - 3

Solution steps

4 (x + 3)^{2} + 2 = - 6

Move

2

to the right side

4 (x + 3)^{2} = - 8

Divide both sides by

4

(x + 3)^{2} = - 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = - 2 : x = 2 i - 3

Solve

x + 3 = - - 2 : x = - 2 i - 3

The solutions to the quadratic equation are:

x = 2 i - 3, x = - 2 i - 3

(x + 3) (x - 3) = x (4 x + 5)

y, y^{2} = 5 - X

3 (x^{2} + 1) = x (x - 3)

x, 2 y x^{2} - 4 x - y + 4 = 0

x^{2} - 24 + 5 x = 0

What are the solutions to the equation 4(x+3)^2+2=-6 ?
The solutions to the equation 4(x+3)^2+2=-6 are x=sqrt(2)i-3,x=-sqrt(2)i-3
Find the zeros of 4(x+3)^2+2=-6
The zeros of 4(x+3)^2+2=-6 are x=sqrt(2)i-3,x=-sqrt(2)i-3