What are the solutions to the equation x^2-9x+81/4 =0 ?

The solutions to the equation x^2-9x+81/4 =0 are x= 9/2

Find the zeros of x^2-9x+81/4 =0

The zeros of x^2-9x+81/4 =0 are x= 9/2

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x^{2} - 9 x + \frac{81}{4} = 0

x = \frac{9}{2}

Decimal Notation

x = 4.5

Solution steps

x^{2} - 9 x + \frac{81}{4} = 0

Multiply both sides by

4

4 x^{2} - 36 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 4 \cdot 81}{2 \cdot 4}

(- 36)^{2} - 4 \cdot 4 \cdot 81 = 0

x_{1, 2} = \frac{- ( - 36 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 36 )}{2 \cdot 4}

\frac{- ( - 36 )}{2 \cdot 4} = \frac{9}{2}

x = \frac{9}{2}

The solution to the quadratic equation is:

x = \frac{9}{2}

a^{2} - 16 = 32

(3 x + 2)^{2} = 49

2 y (8 y + 3) = 1

0 = 5 - \frac{1}{2} x^{2}

(2 x - 7) (4 x + 3) = 112

What are the solutions to the equation x^2-9x+81/4 =0 ?
The solutions to the equation x^2-9x+81/4 =0 are x= 9/2
Find the zeros of x^2-9x+81/4 =0
The zeros of x^2-9x+81/4 =0 are x= 9/2