What are the solutions to the equation m^2+2m-120=0 ?

The solutions to the equation m^2+2m-120=0 are m=10,m=-12

Find the zeros of m^2+2m-120=0

The zeros of m^2+2m-120=0 are m=10,m=-12

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m^{2} + 2 m - 120 = 0

m = 10, m = - 12

Solution steps

m^{2} + 2 m - 120 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 120 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 120) = 22

m_{1, 2} = \frac{- 2 \pm 22}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 2 + 22}{2 \cdot 1}, m_{2} = \frac{- 2 - 22}{2 \cdot 1}

m = \frac{- 2 + 22}{2 \cdot 1} : 10

m = \frac{- 2 - 22}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

m = 10, m = - 12

2 x^{2} - 3 x + 1 = \frac{3}{8}

(x - 2)^{2} + (x + 8)^{2} = 1 0^{2}

3 x^{2} + 3 x = 25 x - x^{2}

5 x^{2} + 5 = - 15

2 x^{2} - 6 = 3 x

What are the solutions to the equation m^2+2m-120=0 ?
The solutions to the equation m^2+2m-120=0 are m=10,m=-12
Find the zeros of m^2+2m-120=0
The zeros of m^2+2m-120=0 are m=10,m=-12