What are the solutions to the equation 7x+120=x^2 ?

The solutions to the equation 7x+120=x^2 are x=15,x=-8

Find the zeros of 7x+120=x^2

The zeros of 7x+120=x^2 are x=15,x=-8

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7 x + 120 = x^{2}

x = 15, x = - 8

Solution steps

7 x + 120 = x^{2}

Switch sides

x^{2} = 7 x + 120

Move

120

to the left side

x^{2} - 120 = 7 x

Move

7 x

to the left side

x^{2} - 120 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 7 x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 120 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 120) = 23

x_{1, 2} = \frac{- ( - 7 ) \pm 23}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 23}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 23}{2 \cdot 1}

x = \frac{- ( - 7 ) + 23}{2 \cdot 1} : 15

x = \frac{- ( - 7 ) - 23}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 15, x = - 8

2 a^{2} + 11 a - 21 = 0

3 x^{2} - \frac{1}{75} = 0

x^{2} = - 13 x

9 x^{2} - 5 = 4

x^{2} - 100 x + 2100 = 0

What are the solutions to the equation 7x+120=x^2 ?
The solutions to the equation 7x+120=x^2 are x=15,x=-8
Find the zeros of 7x+120=x^2
The zeros of 7x+120=x^2 are x=15,x=-8