What are the solutions to the equation 49x^2+1=25 ?

The solutions to the equation 49x^2+1=25 are x=(2sqrt(6))/7 ,x=-(2sqrt(6))/7

Find the zeros of 49x^2+1=25

The zeros of 49x^2+1=25 are x=(2sqrt(6))/7 ,x=-(2sqrt(6))/7

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49 x^{2} + 1 = 25

x = \frac{2 6}{7}, x = - \frac{2 6}{7}

Decimal

x = 0.69985 \dots, x = - 0.69985 \dots

Solution steps

49 x^{2} + 1 = 25

Move

1

to the right side

49 x^{2} = 24

Divide both sides by

49

x^{2} = \frac{24}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{24}{49}, x = - \frac{24}{49}

\frac{24}{49} = \frac{2 6}{7}

- \frac{24}{49} = - \frac{2 6}{7}

x = \frac{2 6}{7}, x = - \frac{2 6}{7}

5 x^{2} - 30 x + 25 = 0

x - x^{2} + 3 = 4 x^{2} + 2

2 x (5 x - 3) = 0

y, h = 16 - 3 y^{2}

x^{2} + 10 x = 5

What are the solutions to the equation 49x^2+1=25 ?
The solutions to the equation 49x^2+1=25 are x=(2sqrt(6))/7 ,x=-(2sqrt(6))/7
Find the zeros of 49x^2+1=25
The zeros of 49x^2+1=25 are x=(2sqrt(6))/7 ,x=-(2sqrt(6))/7