What are the solutions to the equation 0=x^2-12x+1 ?

The solutions to the equation 0=x^2-12x+1 are x=6+sqrt(35),x=6-sqrt(35)

Find the zeros of 0=x^2-12x+1

The zeros of 0=x^2-12x+1 are x=6+sqrt(35),x=6-sqrt(35)

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0 = x^{2} - 12 x + 1

x = 6 + 35, x = 6 - 35

Decimal Notation

x = 11.91607 \dots, x = 0.08392 \dots

Solution steps

0 = x^{2} - 12 x + 1

Switch sides

x^{2} - 12 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 1 = 235

x_{1, 2} = \frac{- ( - 12 ) \pm 2 35}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 35}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 35}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 35}{2 \cdot 1} : 6 + 35

x = \frac{- ( - 12 ) - 2 35}{2 \cdot 1} : 6 - 35

The solutions to the quadratic equation are:

x = 6 + 35, x = 6 - 35

4 x^{2} - 16 x + 22

x, 3 x - x^{2} - 6 x y = 0

(x + 5) (x - 5) - 5 (x - 4) = (x - 4) 2

x^{2} - 2 a x = - (a^{2} - b^{2})

6 v^{2} - 30 = 0

What are the solutions to the equation 0=x^2-12x+1 ?
The solutions to the equation 0=x^2-12x+1 are x=6+sqrt(35),x=6-sqrt(35)
Find the zeros of 0=x^2-12x+1
The zeros of 0=x^2-12x+1 are x=6+sqrt(35),x=6-sqrt(35)