What are the solutions to the equation (3x+4)(x+2)=0 ?

The solutions to the equation (3x+4)(x+2)=0 are x=-4/3 ,x=-2

Find the zeros of (3x+4)(x+2)=0

The zeros of (3x+4)(x+2)=0 are x=-4/3 ,x=-2

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(3 x + 4) (x + 2) = 0

x = - \frac{4}{3}, x = - 2

Decimal Notation

x = - 1.33333 \dots, x = - 2

Solution steps

(3 x + 4) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 4 = 0 or x + 2 = 0

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = - 2

m^{2} + 8 m = - 16

3 x^{2} = - 6 x

(x - 3)^{2} + 4 = - x^{2}

2 x^{2} - 5 x = x^{2} + 2 x - 1

9 x^{2} - 12 x = 14

What are the solutions to the equation (3x+4)(x+2)=0 ?
The solutions to the equation (3x+4)(x+2)=0 are x=-4/3 ,x=-2
Find the zeros of (3x+4)(x+2)=0
The zeros of (3x+4)(x+2)=0 are x=-4/3 ,x=-2