What are the solutions to the equation x^2+8=-6x ?

The solutions to the equation x^2+8=-6x are x=-2,x=-4

Find the zeros of x^2+8=-6x

The zeros of x^2+8=-6x are x=-2,x=-4

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x^{2} + 8 = - 6 x

x = - 2, x = - 4

Solution steps

x^{2} + 8 = - 6 x

Move

6 x

to the left side

x^{2} + 8 + 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 8 = 2

x_{1, 2} = \frac{- 6 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2}{2 \cdot 1}, x_{2} = \frac{- 6 - 2}{2 \cdot 1}

x = \frac{- 6 + 2}{2 \cdot 1} : - 2

x = \frac{- 6 - 2}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 2, x = - 4

- 5 (t^{2} - 3) + 15 = - 2 t

x^{2} + 6 x - 21 = 0

x^{2} = 15 - 2 x

- x + 4 x (2 - x) = - 1

l (x) = - x^{2} + 12 x - 20

What are the solutions to the equation x^2+8=-6x ?
The solutions to the equation x^2+8=-6x are x=-2,x=-4
Find the zeros of x^2+8=-6x
The zeros of x^2+8=-6x are x=-2,x=-4