What are the solutions to the equation x^2+16x+5=0 ?

The solutions to the equation x^2+16x+5=0 are x=-8+sqrt(59),x=-8-sqrt(59)

Find the zeros of x^2+16x+5=0

The zeros of x^2+16x+5=0 are x=-8+sqrt(59),x=-8-sqrt(59)

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x^{2} + 16 x + 5 = 0

x = - 8 + 59, x = - 8 - 59

Decimal Notation

x = - 0.31885 \dots, x = - 15.68114 \dots

Solution steps

x^{2} + 16 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 5 = 259

x_{1, 2} = \frac{- 16 \pm 2 59}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 59}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 59}{2 \cdot 1}

x = \frac{- 16 + 2 59}{2 \cdot 1} : - 8 + 59

x = \frac{- 16 - 2 59}{2 \cdot 1} : - 8 - 59

The solutions to the quadratic equation are:

x = - 8 + 59, x = - 8 - 59

(4 x^{2} y)^{3}

- 7 + 6 x = x + 8

8 - (x + h)^{3}

2 x + 5 x + 15 = 90

2.4 (n - 1) = 12

What are the solutions to the equation x^2+16x+5=0 ?
The solutions to the equation x^2+16x+5=0 are x=-8+sqrt(59),x=-8-sqrt(59)
Find the zeros of x^2+16x+5=0
The zeros of x^2+16x+5=0 are x=-8+sqrt(59),x=-8-sqrt(59)