What are the solutions to the equation 12h^2-h-6=0 ?

The solutions to the equation 12h^2-h-6=0 are h= 3/4 ,h=-2/3

Find the zeros of 12h^2-h-6=0

The zeros of 12h^2-h-6=0 are h= 3/4 ,h=-2/3

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12 h^{2} - h - 6 = 0

h = \frac{3}{4}, h = - \frac{2}{3}

Decimal Notation

h = 0.75, h = - 0.66666 \dots

Solution steps

12 h^{2} - h - 6 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 12 ( - 6 )}{2 \cdot 12}

(- 1)^{2} - 4 \cdot 12 (- 6) = 17

h_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 12}

Separate the solutions

h_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 12}, h_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 12}

h = \frac{- ( - 1 ) + 17}{2 \cdot 12} : \frac{3}{4}

h = \frac{- ( - 1 ) - 17}{2 \cdot 12} : - \frac{2}{3}

The solutions to the quadratic equation are:

h = \frac{3}{4}, h = - \frac{2}{3}

3 x^{2} - 5 = 34

6 x^{2} + x = 0

2 x + 3 = x^{2} + 3

4 x^{2} - 8 x - 16

10 z^{2} - 7 = 7 z^{2} + 3

What are the solutions to the equation 12h^2-h-6=0 ?
The solutions to the equation 12h^2-h-6=0 are h= 3/4 ,h=-2/3
Find the zeros of 12h^2-h-6=0
The zeros of 12h^2-h-6=0 are h= 3/4 ,h=-2/3