What are the solutions to the equation 5-2x^2=6 ?

The solutions to the equation 5-2x^2=6 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i

Find the zeros of 5-2x^2=6

The zeros of 5-2x^2=6 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i

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5 - 2 x^{2} = 6

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

5 - 2 x^{2} = 6

Move

5

to the right side

- 2 x^{2} = 1

Divide both sides by

- 2

x^{2} = - \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{2}, x = - - \frac{1}{2}

- \frac{1}{2} = \frac{1}{2} i

- - \frac{1}{2} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

(3 x - 2)^{2} = 9 x + 2

x + 3 x^{2} = 0

m^{2} - 9 m + 9 = 0

7 u^{2} + 2 u - 15 = 0

3 x^{2} - 6 x + 17

What are the solutions to the equation 5-2x^2=6 ?
The solutions to the equation 5-2x^2=6 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i
Find the zeros of 5-2x^2=6
The zeros of 5-2x^2=6 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i