What are the solutions to the equation s(11-s)=24 ?

The solutions to the equation s(11-s)=24 are s=3,s=8

Find the zeros of s(11-s)=24

The zeros of s(11-s)=24 are s=3,s=8

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s (11 - s) = 24

s = 3, s = 8

Solution steps

s (11 - s) = 24

Expand

s (11 - s) : 11 s - s^{2}

11 s - s^{2} = 24

Move

24

to the left side

11 s - s^{2} - 24 = 0

Write in the standard form

a x^{2} + b x + c = 0

- s^{2} + 11 s - 24 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 ( - 1 ) ( - 24 )}{2 ( - 1 )}

1 1^{2} - 4 (- 1) (- 24) = 5

s_{1, 2} = \frac{- 11 \pm 5}{2 ( - 1 )}

Separate the solutions

s_{1} = \frac{- 11 + 5}{2 ( - 1 )}, s_{2} = \frac{- 11 - 5}{2 ( - 1 )}

s = \frac{- 11 + 5}{2 ( - 1 )} : 3

s = \frac{- 11 - 5}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

s = 3, s = 8

5 x^{2} - 3 (2 x - 1) = 2 x^{2} - 8 x

8 x^{2} - 24 = 8

2 x^{2} - 3 x + 4 = x^{2} + 5 x - 3

3 x + x^{2} - 33 - x 3 = 0

x, x^{2} + 5 x + 2 = - 4 es

What are the solutions to the equation s(11-s)=24 ?
The solutions to the equation s(11-s)=24 are s=3,s=8
Find the zeros of s(11-s)=24
The zeros of s(11-s)=24 are s=3,s=8