What are the solutions to the equation 3x^2-6x=-5 ?

The solutions to the equation 3x^2-6x=-5 are x=1+isqrt(2/3),x=1-isqrt(2/3)

Find the zeros of 3x^2-6x=-5

The zeros of 3x^2-6x=-5 are x=1+isqrt(2/3),x=1-isqrt(2/3)

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3 x^{2} - 6 x = - 5

x = 1 + i \frac{2}{3}, x = 1 - i \frac{2}{3}

Solution steps

3 x^{2} - 6 x = - 5

Move

5

to the left side

3 x^{2} - 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

(- 6)^{2} - 4 \cdot 3 \cdot 5 : 26 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 6 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 6 i}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 2 6 i}{2 \cdot 3}

x = \frac{- ( - 6 ) + 2 6 i}{2 \cdot 3} : 1 + i \frac{2}{3}

x = \frac{- ( - 6 ) - 2 6 i}{2 \cdot 3} : 1 - i \frac{2}{3}

The solutions to the quadratic equation are:

x = 1 + i \frac{2}{3}, x = 1 - i \frac{2}{3}

x^{2} + x - 30 = 0

200 = 0.1 w^{2} + 2.155 w + 19.985

x^{2} - 8 x - 5 = 7

2 w^{2} - 5 w - 14 = - 5

3 x^{2} + 6 x + 1

What are the solutions to the equation 3x^2-6x=-5 ?
The solutions to the equation 3x^2-6x=-5 are x=1+isqrt(2/3),x=1-isqrt(2/3)
Find the zeros of 3x^2-6x=-5
The zeros of 3x^2-6x=-5 are x=1+isqrt(2/3),x=1-isqrt(2/3)