What are the solutions to the equation 2+x-6x^2=0 ?

The solutions to the equation 2+x-6x^2=0 are x=-1/2 ,x= 2/3

Find the zeros of 2+x-6x^2=0

The zeros of 2+x-6x^2=0 are x=-1/2 ,x= 2/3

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2 + x - 6 x^{2} = 0

x = - \frac{1}{2}, x = \frac{2}{3}

Decimal Notation

x = - 0.5, x = 0.66666 \dots

Solution steps

2 + x - 6 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 6 x^{2} + x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 6 ) \cdot 2}{2 ( - 6 )}

1^{2} - 4 (- 6) \cdot 2 = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 ( - 6 )}, x_{2} = \frac{- 1 - 7}{2 ( - 6 )}

x = \frac{- 1 + 7}{2 ( - 6 )} : - \frac{1}{2}

x = \frac{- 1 - 7}{2 ( - 6 )} : \frac{2}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = \frac{2}{3}

\frac{t ^{2} - 1}{3} = t^{2} - 51

a, 9 a = 16 - a^{2}

4 x^{2} - x - 9 = 0

3 x (x + 2) = 3

(3 x - 8) (x + 2) = 2 x^{2}

What are the solutions to the equation 2+x-6x^2=0 ?
The solutions to the equation 2+x-6x^2=0 are x=-1/2 ,x= 2/3
Find the zeros of 2+x-6x^2=0
The zeros of 2+x-6x^2=0 are x=-1/2 ,x= 2/3