What are the solutions to the equation 5(x+2)^2+23(x+2)+12=0 ?

The solutions to the equation 5(x+2)^2+23(x+2)+12=0 are x=-13/5 ,x=-6

Find the zeros of 5(x+2)^2+23(x+2)+12=0

The zeros of 5(x+2)^2+23(x+2)+12=0 are x=-13/5 ,x=-6

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5 (x + 2)^{2} + 23 (x + 2) + 12 = 0

x = - \frac{13}{5}, x = - 6

Decimal Notation

x = - 2.6, x = - 6

Solution steps

5 (x + 2)^{2} + 23 (x + 2) + 12 = 0

Expand

5 (x + 2)^{2} + 23 (x + 2) + 12 : 5 x^{2} + 43 x + 78

5 x^{2} + 43 x + 78 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 43 \pm 4 3 ^{2} - 4 \cdot 5 \cdot 78}{2 \cdot 5}

4 3^{2} - 4 \cdot 5 \cdot 78 = 17

x_{1, 2} = \frac{- 43 \pm 17}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 43 + 17}{2 \cdot 5}, x_{2} = \frac{- 43 - 17}{2 \cdot 5}

x = \frac{- 43 + 17}{2 \cdot 5} : - \frac{13}{5}

x = \frac{- 43 - 17}{2 \cdot 5} : - 6

The solutions to the quadratic equation are:

x = - \frac{13}{5}, x = - 6

w^{2} = 6 w

7 a^{2} - 300 = 43

9 y^{2} - 12 y + 7 = 0

(5 x + 4) (x + 1) = 2

3 - 2 x^{2} = 7

What are the solutions to the equation 5(x+2)^2+23(x+2)+12=0 ?
The solutions to the equation 5(x+2)^2+23(x+2)+12=0 are x=-13/5 ,x=-6
Find the zeros of 5(x+2)^2+23(x+2)+12=0
The zeros of 5(x+2)^2+23(x+2)+12=0 are x=-13/5 ,x=-6