What are the solutions to the equation 3x^2-x^2+7x+3=4 ?

The solutions to the equation 3x^2-x^2+7x+3=4 are x=(-7+sqrt(57))/4 ,x=(-7-sqrt(57))/4

Find the zeros of 3x^2-x^2+7x+3=4

The zeros of 3x^2-x^2+7x+3=4 are x=(-7+sqrt(57))/4 ,x=(-7-sqrt(57))/4

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3 x^{2} - x^{2} + 7 x + 3 = 4

x = \frac{- 7 + 57}{4}, x = \frac{- 7 - 57}{4}

Solution steps

3 x^{2} - x^{2} + 7 x + 3 = 4

Refine

2 x^{2} + 7 x + 3 = 4

Move

4

to the left side

2 x^{2} + 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 1) = 57

x_{1, 2} = \frac{- 7 \pm 57}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 57}{2 \cdot 2}, x_{2} = \frac{- 7 - 57}{2 \cdot 2}

x = \frac{- 7 + 57}{2 \cdot 2} : \frac{- 7 + 57}{4}

x = \frac{- 7 - 57}{2 \cdot 2} : \frac{- 7 - 57}{4}

The solutions to the quadratic equation are:

x = \frac{- 7 + 57}{4}, x = \frac{- 7 - 57}{4}

3 x^{2} - 6 x - 22 = 0

(x + 8) (x - 5) = 0

- 2 x^{2} + 4 x - 9 = 0

2 x^{2} = 9 x + 18

x^{2} - 6 x + 9 = 8

What are the solutions to the equation 3x^2-x^2+7x+3=4 ?
The solutions to the equation 3x^2-x^2+7x+3=4 are x=(-7+sqrt(57))/4 ,x=(-7-sqrt(57))/4
Find the zeros of 3x^2-x^2+7x+3=4
The zeros of 3x^2-x^2+7x+3=4 are x=(-7+sqrt(57))/4 ,x=(-7-sqrt(57))/4