What are the solutions to the equation c^2-9c+11=0 ?

The solutions to the equation c^2-9c+11=0 are c=(9+sqrt(37))/2 ,c=(9-sqrt(37))/2

Find the zeros of c^2-9c+11=0

The zeros of c^2-9c+11=0 are c=(9+sqrt(37))/2 ,c=(9-sqrt(37))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

c^{2} - 9 c + 11 = 0

c = \frac{9 + 37}{2}, c = \frac{9 - 37}{2}

Decimal Notation

c = 7.54138 \dots, c = 1.45861 \dots

Solution steps

c^{2} - 9 c + 11 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 11 = 37

c_{1, 2} = \frac{- ( - 9 ) \pm 37}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 9 ) + 37}{2 \cdot 1}, c_{2} = \frac{- ( - 9 ) - 37}{2 \cdot 1}

c = \frac{- ( - 9 ) + 37}{2 \cdot 1} : \frac{9 + 37}{2}

c = \frac{- ( - 9 ) - 37}{2 \cdot 1} : \frac{9 - 37}{2}

The solutions to the quadratic equation are:

c = \frac{9 + 37}{2}, c = \frac{9 - 37}{2}

3 x^{2} - 6 = (x + 2) (x - 3)

8 f^{2} + 11 f = 2 f^{2} + 3 (2 f - 5) + 21

y, 3 y - 2 x y - 3 y^{2} = 0

(2 x - 1) (x + 3) = - 2 x

a x^{2} + 2 x + a = 5 x^{2} - 3 a x + 4

What are the solutions to the equation c^2-9c+11=0 ?
The solutions to the equation c^2-9c+11=0 are c=(9+sqrt(37))/2 ,c=(9-sqrt(37))/2
Find the zeros of c^2-9c+11=0
The zeros of c^2-9c+11=0 are c=(9+sqrt(37))/2 ,c=(9-sqrt(37))/2