What are the solutions to the equation 3/4 x^2+12=0 ?

The solutions to the equation 3/4 x^2+12=0 are x=4i,x=-4i

Find the zeros of 3/4 x^2+12=0

The zeros of 3/4 x^2+12=0 are x=4i,x=-4i

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\frac{3}{4} x^{2} + 12 = 0

x = 4 i, x = - 4 i

Solution steps

\frac{3}{4} x^{2} + 12 = 0

Move

12

to the right side

\frac{3}{4} x^{2} = - 12

Multiply both sides by

4

3 x^{2} = - 48

Divide both sides by

3

x^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 16, x = - - 16

- 16 = 4 i

- - 16 = - 4 i

x = 4 i, x = - 4 i

2 x^{2} - 5 x - 3

2 x^{3} - 12 x^{2} + 18 - 3 x

3 ∣ 2 x - 7 ∣ = 15

∣ 2 + 3 i ∣

16 k - 24

What are the solutions to the equation 3/4 x^2+12=0 ?
The solutions to the equation 3/4 x^2+12=0 are x=4i,x=-4i
Find the zeros of 3/4 x^2+12=0
The zeros of 3/4 x^2+12=0 are x=4i,x=-4i