What are the solutions to the equation 4x^2-x=2x^2+7x ?

The solutions to the equation 4x^2-x=2x^2+7x are x=4,x=0

Find the zeros of 4x^2-x=2x^2+7x

The zeros of 4x^2-x=2x^2+7x are x=4,x=0

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4 x^{2} - x = 2 x^{2} + 7 x

x = 4, x = 0

Solution steps

4 x^{2} - x = 2 x^{2} + 7 x

Move

7 x

to the left side

4 x^{2} - 8 x = 2 x^{2}

Move

2 x^{2}

to the left side

2 x^{2} - 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 0 = 8

x_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 2}

x = \frac{- ( - 8 ) + 8}{2 \cdot 2} : 4

x = \frac{- ( - 8 ) - 8}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

3 x^{2} - 6 x + 15

2 x^{2} + 20 + 10 x = 4 x^{2} + 28

X^{2} - 2 (X) (4) - (- 4)^{2} = 2 (X + 8)

(5 p + 3)^{2} = 8

2 x^{2} - 4 x + 17

What are the solutions to the equation 4x^2-x=2x^2+7x ?
The solutions to the equation 4x^2-x=2x^2+7x are x=4,x=0
Find the zeros of 4x^2-x=2x^2+7x
The zeros of 4x^2-x=2x^2+7x are x=4,x=0