What are the solutions to the equation y^2+20(y+5)=0 ?

The solutions to the equation y^2+20(y+5)=0 are y=-10

Find the zeros of y^2+20(y+5)=0

The zeros of y^2+20(y+5)=0 are y=-10

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y^{2} + 20 (y + 5) = 0

y = - 10

Solution steps

y^{2} + 20 (y + 5) = 0

Expand

y^{2} + 20 (y + 5) : y^{2} + 20 y + 100

y^{2} + 20 y + 100 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 100}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 100 = 0

y_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 1}

y = \frac{- 20}{2 \cdot 1}

\frac{- 20}{2 \cdot 1} = - 10

y = - 10

The solution to the quadratic equation is:

y = - 10

x^{2} + 5 x - 16 = 0

(x + 4)^{2} + 8 = 0

w^{2} - 8 w + 12 = 0

4 = x^{2} + 3 x

x^{2} + 21 x + 108 = 0

What are the solutions to the equation y^2+20(y+5)=0 ?
The solutions to the equation y^2+20(y+5)=0 are y=-10
Find the zeros of y^2+20(y+5)=0
The zeros of y^2+20(y+5)=0 are y=-10