What are the solutions to the equation 28x^2-x-2=0 ?

The solutions to the equation 28x^2-x-2=0 are x= 2/7 ,x=-1/4

Find the zeros of 28x^2-x-2=0

The zeros of 28x^2-x-2=0 are x= 2/7 ,x=-1/4

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28 x^{2} - x - 2 = 0

x = \frac{2}{7}, x = - \frac{1}{4}

Decimal Notation

x = 0.28571 \dots, x = - 0.25

Solution steps

28 x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 28 ( - 2 )}{2 \cdot 28}

(- 1)^{2} - 4 \cdot 28 (- 2) = 15

x_{1, 2} = \frac{- ( - 1 ) \pm 15}{2 \cdot 28}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 15}{2 \cdot 28}, x_{2} = \frac{- ( - 1 ) - 15}{2 \cdot 28}

x = \frac{- ( - 1 ) + 15}{2 \cdot 28} : \frac{2}{7}

x = \frac{- ( - 1 ) - 15}{2 \cdot 28} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{2}{7}, x = - \frac{1}{4}

- 2 p^{2} + 7 p - 4 = - 3 p^{2}

(x - 8)^{2} - 2 x = 7

3 x^{2} + 5 x = 12

25 b^{2} - 16 = 0

3.5 x^{2} - 5 x - 2.5 = 0

What are the solutions to the equation 28x^2-x-2=0 ?
The solutions to the equation 28x^2-x-2=0 are x= 2/7 ,x=-1/4
Find the zeros of 28x^2-x-2=0
The zeros of 28x^2-x-2=0 are x= 2/7 ,x=-1/4