What are the solutions to the equation solvefor x,x^2-8x+by+8=0 ?

The solutions to the equation solvefor x,x^2-8x+by+8=0 are x=4+sqrt(-by+8),x=4-sqrt(-by+8)

Find the zeros of solvefor x,x^2-8x+by+8=0

The zeros of solvefor x,x^2-8x+by+8=0 are x=4+sqrt(-by+8),x=4-sqrt(-by+8)

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solve for

x, x^{2} - 8 x + b y + 8 = 0

x = 4 + - b y + 8, x = 4 - - b y + 8

Solution steps

x^{2} - 8 x + b y + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( b y + 8 )}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot (b y + 8) : 2 - b y + 8

x_{1, 2} = \frac{- ( - 8 ) \pm 2 - b y + 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 - b y + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 - b y + 8}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 - b y + 8}{2 \cdot 1} : 4 + - b y + 8

x = \frac{- ( - 8 ) - 2 - b y + 8}{2 \cdot 1} : 4 - - b y + 8

The solutions to the quadratic equation are:

x = 4 + - b y + 8, x = 4 - - b y + 8

(x + 6)^{2} = - 1

x, x^{2} y - 2 x + y - 1 = 0

3 w^{2} + 8 w = 0

4 t^{2} - 20 t + 25 = 0

3 x (2 + 2 x) = x (5 x - 5)

What are the solutions to the equation solvefor x,x^2-8x+by+8=0 ?
The solutions to the equation solvefor x,x^2-8x+by+8=0 are x=4+sqrt(-by+8),x=4-sqrt(-by+8)
Find the zeros of solvefor x,x^2-8x+by+8=0
The zeros of solvefor x,x^2-8x+by+8=0 are x=4+sqrt(-by+8),x=4-sqrt(-by+8)