What are the solutions to the equation -15x^2+x+28=0 ?

The solutions to the equation -15x^2+x+28=0 are x=-4/3 ,x= 7/5

Find the zeros of -15x^2+x+28=0

The zeros of -15x^2+x+28=0 are x=-4/3 ,x= 7/5

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- 15 x^{2} + x + 28 = 0

x = - \frac{4}{3}, x = \frac{7}{5}

Decimal Notation

x = - 1.33333 \dots, x = 1.4

Solution steps

- 15 x^{2} + x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 15 ) \cdot 28}{2 ( - 15 )}

1^{2} - 4 (- 15) \cdot 28 = 41

x_{1, 2} = \frac{- 1 \pm 41}{2 ( - 15 )}

Separate the solutions

x_{1} = \frac{- 1 + 41}{2 ( - 15 )}, x_{2} = \frac{- 1 - 41}{2 ( - 15 )}

x = \frac{- 1 + 41}{2 ( - 15 )} : - \frac{4}{3}

x = \frac{- 1 - 41}{2 ( - 15 )} : \frac{7}{5}

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = \frac{7}{5}

(a - 5)^{2} = 2 a

3 x^{2} + 12 x = 7 x + 2

12 - t^{2} = 13

6 y^{2} - y + 3 = 0

3 x^{2} = 5 - 2 x

What are the solutions to the equation -15x^2+x+28=0 ?
The solutions to the equation -15x^2+x+28=0 are x=-4/3 ,x= 7/5
Find the zeros of -15x^2+x+28=0
The zeros of -15x^2+x+28=0 are x=-4/3 ,x= 7/5