What are the solutions to the equation (x+3)^2=3-x ?

The solutions to the equation (x+3)^2=3-x are x=-1,x=-6

Find the zeros of (x+3)^2=3-x

The zeros of (x+3)^2=3-x are x=-1,x=-6

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(x + 3)^{2} = 3 - x

x = - 1, x = - 6

Solution steps

(x + 3)^{2} = 3 - x

Expand

(x + 3)^{2} : x^{2} + 6 x + 9

x^{2} + 6 x + 9 = 3 - x

Move

x

to the left side

x^{2} + 7 x + 9 = 3

Move

3

to the left side

x^{2} + 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 6 = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 \cdot 1}, x_{2} = \frac{- 7 - 5}{2 \cdot 1}

x = \frac{- 7 + 5}{2 \cdot 1} : - 1

x = \frac{- 7 - 5}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 1, x = - 6

x^{2} + 14 x + 64 = 0

r^{2} - 32 = 0

9 x - 3 x^{2} = 6

- 3 x^{2} - 36 x - 104

x, x^{2} y^{3} + 2 x = 6 y - 10

What are the solutions to the equation (x+3)^2=3-x ?
The solutions to the equation (x+3)^2=3-x are x=-1,x=-6
Find the zeros of (x+3)^2=3-x
The zeros of (x+3)^2=3-x are x=-1,x=-6