What are the solutions to the equation 4x^2-4x+7x-7=2 ?

The solutions to the equation 4x^2-4x+7x-7=2 are x=(-3+3sqrt(17))/8 ,x=(-3-3sqrt(17))/8

Find the zeros of 4x^2-4x+7x-7=2

The zeros of 4x^2-4x+7x-7=2 are x=(-3+3sqrt(17))/8 ,x=(-3-3sqrt(17))/8

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4 x^{2} - 4 x + 7 x - 7 = 2

x = \frac{- 3 + 3 17}{8}, x = \frac{- 3 - 3 17}{8}

Decimal Notation

x = 1.17116 \dots, x = - 1.92116 \dots

Solution steps

4 x^{2} - 4 x + 7 x - 7 = 2

Refine

4 x^{2} + 3 x - 7 = 2

Move

2

to the left side

4 x^{2} + 3 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 9) = 317

x_{1, 2} = \frac{- 3 \pm 3 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 3 17}{2 \cdot 4}, x_{2} = \frac{- 3 - 3 17}{2 \cdot 4}

x = \frac{- 3 + 3 17}{2 \cdot 4} : \frac{- 3 + 3 17}{8}

x = \frac{- 3 - 3 17}{2 \cdot 4} : \frac{- 3 - 3 17}{8}

The solutions to the quadratic equation are:

x = \frac{- 3 + 3 17}{8}, x = \frac{- 3 - 3 17}{8}

8 x + 2 + 5 x^{2} = 4

2 x (9 - 5 x) = - 5 x (2 - 3 x)

(3 y - 5) (2 y + 7) = 0

\frac{x ^{2}}{2} + x - 4 = 0

2 n^{2} - 9 n - 2 = 0

What are the solutions to the equation 4x^2-4x+7x-7=2 ?
The solutions to the equation 4x^2-4x+7x-7=2 are x=(-3+3sqrt(17))/8 ,x=(-3-3sqrt(17))/8
Find the zeros of 4x^2-4x+7x-7=2
The zeros of 4x^2-4x+7x-7=2 are x=(-3+3sqrt(17))/8 ,x=(-3-3sqrt(17))/8