What are the solutions to the equation 2q^2+9q+3=4 ?

The solutions to the equation 2q^2+9q+3=4 are q=(-9+sqrt(89))/4 ,q=(-9-sqrt(89))/4

Find the zeros of 2q^2+9q+3=4

The zeros of 2q^2+9q+3=4 are q=(-9+sqrt(89))/4 ,q=(-9-sqrt(89))/4

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2 q^{2} + 9 q + 3 = 4

q = \frac{- 9 + 89}{4}, q = \frac{- 9 - 89}{4}

Decimal Notation

q = 0.10849 \dots, q = - 4.60849 \dots

Solution steps

2 q^{2} + 9 q + 3 = 4

Move

4

to the left side

2 q^{2} + 9 q - 1 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

9^{2} - 4 \cdot 2 (- 1) = 89

q_{1, 2} = \frac{- 9 \pm 89}{2 \cdot 2}

Separate the solutions

q_{1} = \frac{- 9 + 89}{2 \cdot 2}, q_{2} = \frac{- 9 - 89}{2 \cdot 2}

q = \frac{- 9 + 89}{2 \cdot 2} : \frac{- 9 + 89}{4}

q = \frac{- 9 - 89}{2 \cdot 2} : \frac{- 9 - 89}{4}

The solutions to the quadratic equation are:

q = \frac{- 9 + 89}{4}, q = \frac{- 9 - 89}{4}

2 x (x + 4) = (x - 3)^{2}

x (x + 3) = 16

y, 5 x^{3} - x y^{2} + 3 y = C

7 x^{2} - 10 x = 0

2 x^{2} + 4 x + 11

What are the solutions to the equation 2q^2+9q+3=4 ?
The solutions to the equation 2q^2+9q+3=4 are q=(-9+sqrt(89))/4 ,q=(-9-sqrt(89))/4
Find the zeros of 2q^2+9q+3=4
The zeros of 2q^2+9q+3=4 are q=(-9+sqrt(89))/4 ,q=(-9-sqrt(89))/4