What are the solutions to the equation x(-18+9x)-14=-1 ?

The solutions to the equation x(-18+9x)-14=-1 are x=(3+sqrt(22))/3 ,x=(3-sqrt(22))/3

Find the zeros of x(-18+9x)-14=-1

The zeros of x(-18+9x)-14=-1 are x=(3+sqrt(22))/3 ,x=(3-sqrt(22))/3

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x (- 18 + 9 x) - 14 = - 1

x = \frac{3 + 22}{3}, x = \frac{3 - 22}{3}

Decimal Notation

x = 2.56347 \dots, x = - 0.56347 \dots

Solution steps

x (- 18 + 9 x) - 14 = - 1

Expand

x (- 18 + 9 x) - 14 : - 18 x + 9 x^{2} - 14

- 18 x + 9 x^{2} - 14 = - 1

Move

1

to the left side

9 x^{2} - 18 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 ( - 13 )}{2 \cdot 9}

(- 18)^{2} - 4 \cdot 9 (- 13) = 622

x_{1, 2} = \frac{- ( - 18 ) \pm 6 22}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 22}{2 \cdot 9}, x_{2} = \frac{- ( - 18 ) - 6 22}{2 \cdot 9}

x = \frac{- ( - 18 ) + 6 22}{2 \cdot 9} : \frac{3 + 22}{3}

x = \frac{- ( - 18 ) - 6 22}{2 \cdot 9} : \frac{3 - 22}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 22}{3}, x = \frac{3 - 22}{3}

x - (x + 2) (4 - x) = (x + 1) 2 - 3

6 x^{2} - 6 x = 2

2 x^{2} - 32 = 66

x^{2} = 78

12 = x^{2} + x

What are the solutions to the equation x(-18+9x)-14=-1 ?
The solutions to the equation x(-18+9x)-14=-1 are x=(3+sqrt(22))/3 ,x=(3-sqrt(22))/3
Find the zeros of x(-18+9x)-14=-1
The zeros of x(-18+9x)-14=-1 are x=(3+sqrt(22))/3 ,x=(3-sqrt(22))/3