What are the solutions to the equation 13x^2-52=0 ?

The solutions to the equation 13x^2-52=0 are x=2,x=-2

Find the zeros of 13x^2-52=0

The zeros of 13x^2-52=0 are x=2,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

13 x^{2} - 52 = 0

x = 2, x = - 2

Solution steps

13 x^{2} - 52 = 0

Move

52

to the right side

13 x^{2} = 52

Divide both sides by

13

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

- 8 x - 5 (- 5 x - 1) - 7 = 3 (x - 3) 3 (x - 3)

10 x^{2} + 5 x = 6 x + 3

x, f (h + 1) = 2 x^{2} + 5 x - 3

3 x^{2} - 4 = - 11 x

x, y^{4} = 8 x^{2}

What are the solutions to the equation 13x^2-52=0 ?
The solutions to the equation 13x^2-52=0 are x=2,x=-2
Find the zeros of 13x^2-52=0
The zeros of 13x^2-52=0 are x=2,x=-2