What are the solutions to the equation (2x-1)^2=36 ?

The solutions to the equation (2x-1)^2=36 are x= 7/2 ,x=-5/2

Find the zeros of (2x-1)^2=36

The zeros of (2x-1)^2=36 are x= 7/2 ,x=-5/2

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(2 x - 1)^{2} = 36

x = \frac{7}{2}, x = - \frac{5}{2}

Decimal Notation

x = 3.5, x = - 2.5

Solution steps

(2 x - 1)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 1 = 36 : x = \frac{7}{2}

Solve

2 x - 1 = - 36 : x = - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - \frac{5}{2}

100 = q^{2}

x, f (x + 1) = 3 x^{2} - x + 5

x, ln (y) = a x^{2} + b

x^{2} + 6 x + 8 = 24

- 0.4 x^{2} + 2.2 x + 4.7 = 0

What are the solutions to the equation (2x-1)^2=36 ?
The solutions to the equation (2x-1)^2=36 are x= 7/2 ,x=-5/2
Find the zeros of (2x-1)^2=36
The zeros of (2x-1)^2=36 are x= 7/2 ,x=-5/2