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Popular >

|((x-1))/(x+1)|<1

Solution

\frac{( x - 1 )}{x + 1} < 1

Solution

x > 0

+1

Solution steps

\frac{x - 1}{x + 1} < 1

Apply absolute rule: If

∣ u ∣ < a, a > 0

then

- a < u < a

- 1 < \frac{x - 1}{x + 1} < 1

\frac{x - 1}{x + 1} > - 1 and \frac{x - 1}{x + 1} < 1

(x < - 1 or x > 0) and x > - 1

Merge Overlapping Intervals

x > 0

Popular Examples

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\frac{2}{5} \cdot \frac{1}{2}

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x^{2} - 8 x y - 9 y^{2}

-2>(3(b+4))/(-2)

- 2 > \frac{3 ( b + 4 )}{- 2}

2y+4>-6\lor 4y+2>=-6

2 y + 4 > - 6 or 4 y + 2 \geq - 6

simplify sqrt(12^2+9^2)simplify

1 2^{2} + 9^{2}

Frequently Asked Questions (FAQ)

What is |((x-1))/(x+1)|<1 ?
The solution to |((x-1))/(x+1)|<1 is x>0