What are the solutions to the equation 0.5x^2+x-1.5=0 ?

The solutions to the equation 0.5x^2+x-1.5=0 are x=1,x=-3

Find the zeros of 0.5x^2+x-1.5=0

The zeros of 0.5x^2+x-1.5=0 are x=1,x=-3

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0.5 x^{2} + x - 1.5 = 0

x = 1, x = - 3

Solution steps

0.5 x^{2} + x - 1.5 = 0

Multiply both sides by

10

5 x^{2} + 10 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 5 ( - 15 )}{2 \cdot 5}

1 0^{2} - 4 \cdot 5 (- 15) = 20

x_{1, 2} = \frac{- 10 \pm 20}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 10 + 20}{2 \cdot 5}, x_{2} = \frac{- 10 - 20}{2 \cdot 5}

x = \frac{- 10 + 20}{2 \cdot 5} : 1

x = \frac{- 10 - 20}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

x, x^{2} + y^{2} = 11 x y

2 x^{2} + 7 x - 15

x^{2} - 9 = - 8 x

u^{2} + 2 u + 1 = - 15

t^{2} - 7 t + 6 = 0

What are the solutions to the equation 0.5x^2+x-1.5=0 ?
The solutions to the equation 0.5x^2+x-1.5=0 are x=1,x=-3
Find the zeros of 0.5x^2+x-1.5=0
The zeros of 0.5x^2+x-1.5=0 are x=1,x=-3