What are the solutions to the equation 3(4x-1)^2=27 ?

The solutions to the equation 3(4x-1)^2=27 are x=1,x=-1/2

Find the zeros of 3(4x-1)^2=27

The zeros of 3(4x-1)^2=27 are x=1,x=-1/2

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3 (4 x - 1)^{2} = 27

x = 1, x = - \frac{1}{2}

Decimal Notation

x = 1, x = - 0.5

Solution steps

3 (4 x - 1)^{2} = 27

Divide both sides by

3

(4 x - 1)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 1 = 9 : x = 1

Solve

4 x - 1 = - 9 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{2}

x^{2} = - 2 x + 5

0.1 n^{2} + 100 n + 8 = 86400000

x^{2} + (- \frac{1}{2} x)^{2} = 6

5 x^{2} + 1 = 6

y, (x - 1)^{2} + y^{2} = 25

What are the solutions to the equation 3(4x-1)^2=27 ?
The solutions to the equation 3(4x-1)^2=27 are x=1,x=-1/2
Find the zeros of 3(4x-1)^2=27
The zeros of 3(4x-1)^2=27 are x=1,x=-1/2