What are the solutions to the equation 3(1-4x)-((2x-1)^2)/2 =7 ?

The solutions to the equation 3(1-4x)-((2x-1)^2)/2 =7 are x=-9/2 ,x=-1/2

Find the zeros of 3(1-4x)-((2x-1)^2)/2 =7

The zeros of 3(1-4x)-((2x-1)^2)/2 =7 are x=-9/2 ,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 (1 - 4 x) - \frac{( 2 x - 1 ) ^{2}}{2} = 7

x = - \frac{9}{2}, x = - \frac{1}{2}

Decimal Notation

x = - 4.5, x = - 0.5

Solution steps

3 (1 - 4 x) - \frac{( 2 x - 1 ) ^{2}}{2} = 7

Multiply both sides by

2

6 (1 - 4 x) - (2 x - 1)^{2} = 14

Expand

6 (1 - 4 x) - (2 x - 1)^{2} : - 4 x^{2} - 20 x + 5

- 4 x^{2} - 20 x + 5 = 14

Move

14

to the left side

- 4 x^{2} - 20 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 ( - 4 ) ( - 9 )}{2 ( - 4 )}

(- 20)^{2} - 4 (- 4) (- 9) = 16

x_{1, 2} = \frac{- ( - 20 ) \pm 16}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 16}{2 ( - 4 )}, x_{2} = \frac{- ( - 20 ) - 16}{2 ( - 4 )}

x = \frac{- ( - 20 ) + 16}{2 ( - 4 )} : - \frac{9}{2}

x = \frac{- ( - 20 ) - 16}{2 ( - 4 )} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{9}{2}, x = - \frac{1}{2}

x^{2} + 10 x - 19 = 0

(4 x + 3) - (5 x + 2) (2 x - 5) = 0

- 5 x^{2} - 400 = - 90 x

2 (x^{2} + 2) = - 9 x

3 x (x - 2) = 5

What are the solutions to the equation 3(1-4x)-((2x-1)^2)/2 =7 ?
The solutions to the equation 3(1-4x)-((2x-1)^2)/2 =7 are x=-9/2 ,x=-1/2
Find the zeros of 3(1-4x)-((2x-1)^2)/2 =7
The zeros of 3(1-4x)-((2x-1)^2)/2 =7 are x=-9/2 ,x=-1/2