What are the solutions to the equation (7x+4)^2=4 ?

The solutions to the equation (7x+4)^2=4 are x=-2/7 ,x=-6/7

Find the zeros of (7x+4)^2=4

The zeros of (7x+4)^2=4 are x=-2/7 ,x=-6/7

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(7 x + 4)^{2} = 4

x = - \frac{2}{7}, x = - \frac{6}{7}

Solution steps

(7 x + 4)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

7 x + 4 = 4 : x = - \frac{2}{7}

Solve

7 x + 4 = - 4 : x = - \frac{6}{7}

The solutions to the quadratic equation are:

x = - \frac{2}{7}, x = - \frac{6}{7}

12 a \geq - 24

\frac{2 x - 7}{3} = 5 - \frac{3 x - 2}{4}

- \frac{1}{8} + \frac{5}{6} - \frac{5}{12}

100 0^{\frac{2}{3}}

x^{2} + x^{2} = (x + 3)^{2}

What are the solutions to the equation (7x+4)^2=4 ?
The solutions to the equation (7x+4)^2=4 are x=-2/7 ,x=-6/7
Find the zeros of (7x+4)^2=4
The zeros of (7x+4)^2=4 are x=-2/7 ,x=-6/7