What are the solutions to the equation 4d^2-5d-3=2d ?

The solutions to the equation 4d^2-5d-3=2d are d=(7+sqrt(97))/8 ,d=(7-sqrt(97))/8

Find the zeros of 4d^2-5d-3=2d

The zeros of 4d^2-5d-3=2d are d=(7+sqrt(97))/8 ,d=(7-sqrt(97))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 d^{2} - 5 d - 3 = 2 d

d = \frac{7 + 97}{8}, d = \frac{7 - 97}{8}

Decimal Notation

d = 2.10610 \dots, d = - 0.35610 \dots

Solution steps

4 d^{2} - 5 d - 3 = 2 d

Move

2 d

to the left side

4 d^{2} - 7 d - 3 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 7)^{2} - 4 \cdot 4 (- 3) = 97

d_{1, 2} = \frac{- ( - 7 ) \pm 97}{2 \cdot 4}

Separate the solutions

d_{1} = \frac{- ( - 7 ) + 97}{2 \cdot 4}, d_{2} = \frac{- ( - 7 ) - 97}{2 \cdot 4}

d = \frac{- ( - 7 ) + 97}{2 \cdot 4} : \frac{7 + 97}{8}

d = \frac{- ( - 7 ) - 97}{2 \cdot 4} : \frac{7 - 97}{8}

The solutions to the quadratic equation are:

d = \frac{7 + 97}{8}, d = \frac{7 - 97}{8}

(x + 7) (x - 4) = 0

8 x^{2} - 7 x - 18 = 0

4 y^{2} + 2 y - 2 = 3 y

7 x^{2} + 6 x + 3 = 0

4 x^{2} + 8 x = 5 x^{2} + x

What are the solutions to the equation 4d^2-5d-3=2d ?
The solutions to the equation 4d^2-5d-3=2d are d=(7+sqrt(97))/8 ,d=(7-sqrt(97))/8
Find the zeros of 4d^2-5d-3=2d
The zeros of 4d^2-5d-3=2d are d=(7+sqrt(97))/8 ,d=(7-sqrt(97))/8