What are the solutions to the equation x^2-6x=-10x+12 ?

The solutions to the equation x^2-6x=-10x+12 are x=2,x=-6

Find the zeros of x^2-6x=-10x+12

The zeros of x^2-6x=-10x+12 are x=2,x=-6

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x^{2} - 6 x = - 10 x + 12

x = 2, x = - 6

Solution steps

x^{2} - 6 x = - 10 x + 12

Move

12

to the left side

x^{2} - 6 x - 12 = - 10 x

Move

10 x

to the left side

x^{2} + 4 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 12) = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 \cdot 1}, x_{2} = \frac{- 4 - 8}{2 \cdot 1}

x = \frac{- 4 + 8}{2 \cdot 1} : 2

x = \frac{- 4 - 8}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

2 (x - 3)^{2} - 72 = 0

3 k^{2} - 14 k - 21 = 0

x, x^{2} + 2 k x - 3 = k x^{2} + 1.4

t, s = \frac{1}{6} g t^{2}

7 x^{2} - 200 = 24

What are the solutions to the equation x^2-6x=-10x+12 ?
The solutions to the equation x^2-6x=-10x+12 are x=2,x=-6
Find the zeros of x^2-6x=-10x+12
The zeros of x^2-6x=-10x+12 are x=2,x=-6