What are the solutions to the equation 12x^2+18x=(12x+18) ?

The solutions to the equation 12x^2+18x=(12x+18) are x=1,x=-3/2

Find the zeros of 12x^2+18x=(12x+18)

The zeros of 12x^2+18x=(12x+18) are x=1,x=-3/2

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12 x^{2} + 18 x = (12 x + 18)

x = 1, x = - \frac{3}{2}

Decimal Notation

x = 1, x = - 1.5

Solution steps

12 x^{2} + 18 x = (12 x + 18)

Refine

12 x^{2} + 18 x = 12 x + 18

Move

18

to the left side

12 x^{2} + 18 x - 18 = 12 x

Move

12 x

to the left side

12 x^{2} + 6 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 12 ( - 18 )}{2 \cdot 12}

6^{2} - 4 \cdot 12 (- 18) = 30

x_{1, 2} = \frac{- 6 \pm 30}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 6 + 30}{2 \cdot 12}, x_{2} = \frac{- 6 - 30}{2 \cdot 12}

x = \frac{- 6 + 30}{2 \cdot 12} : 1

x = \frac{- 6 - 30}{2 \cdot 12} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{3}{2}

(x - 2)^{2} - 6 = 0

- x^{2} - 3 x + 10

3 x^{2} - 14 x - 21 = 0

- 3 x^{2} - 18 x - 26

- 10 x^{2} + x + 21 = 0

What are the solutions to the equation 12x^2+18x=(12x+18) ?
The solutions to the equation 12x^2+18x=(12x+18) are x=1,x=-3/2
Find the zeros of 12x^2+18x=(12x+18)
The zeros of 12x^2+18x=(12x+18) are x=1,x=-3/2